I have two arrays that are the same length, for example var a = [5,2,6,2,7,5]; and var b = [2,3,7,4,3];.
I also have another array which is var c = [0,0,0,0,0];
How do I compare a and b to put the highest element into c which in this case should become [5,3,7,7,5];
Array#map into a new array, and take the max of the current number from a, and the number with the same index from array b:
const a = [5, 2, 6, 2, 7];
const b = [2, 3, 7, 4, 3];
const c = a.map((num, i) => Math.max(num, b[i]));
console.log(c);
You would iterate through both arrays, doing the comparison at each step, and inserting the larger number:
Note: Even though you mention that you have equal length arrays, the two sample arrays you've given don't have the same length so my example uses similar equal-length arrays:
let a = [5, 2, 6, 2, 7]
let b = [2, 3, 7, 4, 3]
let c = [0, 0, 0, 0, 0]
// we can use a single loop index `i` since the arrays have same length
for (let i = 0; i < a.length; i++) {
// take the current number from a and from b
let numA = a[i]
let numB = b[i]
// determine larger of the two numbers
let largerNumber = numA > numB ? numA : numB
// add larger to array at current position
c[i] = largerNumber
}
console.log(c)You can simplify your solution to be a simple map operation, as demonstrated by dhilt.
Just use a simple for loop:
var a = [2, 3, 7, 8];
var b = [3, 2, 5, 9];
var c = [0, 0, 0, 0];
for (var i = 0; i < c.length; i++) {
c[i] = a[i] > b[i] ? a[i] : b[i];
}
console.log("Result: "+c);
see example:
var a = [5,2,6,2,7,5];
var b = [2,3,7,4,3];
var c = [0,0,0,0,0];
for(var i in c){
c[i]=a[i]>b[i]?a[i]:b[i];
}
console.log('result:' + c);
try this, below code takes two arrays and gives the result of max number
var array=[5,3,7,7,5];
var array2 = [5,6,4];
var array3=array.concat(array2);
var max=array3.sort((a,b)=>b-a)[0];
console.log("Result: " + max);
