How to check that none of the chars are in the string?

Question

def lookup(content):
    value=True
    if any(x not in content for x in ['A','B','C']):
        value = False
    print (value)

What i want is check if any of these 'A' 'B' 'C' is in a string , for example if string equates ABCAA then the value will be true, if the string is ABDC then value is wrong because content contains a char not defined in my list above.The issue is i'm getting false with that function for 'ABC' which isn't supposed to happen.

Possible duplicate of [How to check a string for specific characters?](https://stackoverflow.com/questions/5188792/how-to-check-a-string-for-specific-characters) — Jakob, Oct 29 '17 at 19:31

score 1 · Accepted Answer · answered Oct 29 '17 at 19:21

1

Just use sets:

# input
my_string = 'abcd'

# set of allowed characters
approved_characters = set('abc')

# characters in string that are not in set of approved characters
unapproved_characters = set(my_string) - approved_characters # gives {'d'}

answered Oct 29 '17 at 19:21

Reut Sharabani

30,449
6
70
88

score 0 · Answer 2 · answered Oct 29 '17 at 19:27

0

Try this:

def lookup(content):
    print(all(x in ['A','B','C'] for x in content))

lookup('ABC') #output: True

answered Oct 29 '17 at 19:27

gommb

1,121
1
7
21

How to check that none of the chars are in the string?

2 Answers2