How to extract integers from a random string without using regex?

Question

Say I have an arbitrary string like

"abc 123 def 456"

How would I take out the integers so that it can print "123456" without using regex?

I dont think I worded it properly. I edited it so hopefully it makes more sense now. I need to extract the integers from any random string that could be given to me — Spectre, Nov 03 '17 at 03:03
Possible duplicate of [remove numbers string python](https://stackoverflow.com/questions/39906519/remove-numbers-string-python) — Mahesh Karia, Nov 03 '17 at 03:05
You can use `"".join(c for c in s if c.isdigit())`, where `s` is your string. — Tom Karzes, Nov 03 '17 at 03:06

score 0 · Accepted Answer · answered Nov 03 '17 at 03:03

0

for your specific question, you can just use .isdigit()

s = "abc 123 def 456"

for ch in s:
    if ch.isdigit():
        print(ch, end='')
print()

answered Nov 03 '17 at 03:03

0TTT0

please do not encourage zero effort questions – Julien Nov 03 '17 at 03:04
How is it zero effort? I think the first time I posted this it may have seemed like a dumb question, so I editied it.I need to extract the integers out of any string that is given to me, not just the specific one. – Spectre Nov 03 '17 at 03:07
this will extract (print) integers from any given string – 0TTT0 Nov 03 '17 at 03:08
2

@Rionic I understand that very well and my "solution" was sarcastic, but you have shown no code, no search, no effort whatsoever to solve your problem. – Julien Nov 03 '17 at 03:09
This is just a part of my full question, but it's the part I can't figure out, so I decided to just leave out the rest of my code as it would be unecessary. I've been working on the question for quite a while now. – Spectre Nov 03 '17 at 03:13

1 Answers1