How to find index of a value in array with variable length using python

Question

I want to find the index of an array like 3,4,7,8,11,12,14....using python

To find index,I am using below-

alist =[3,4,7,8]
x = int (input))
if x in alist:
    print alist.index(x)

The length of array is not fixed. How do I find index for nth value in array. Do I pass a variable to define array or something? Please help

Possible duplicate of [Finding the index of an item given a list containing it in Python](https://stackoverflow.com/questions/176918/finding-the-index-of-an-item-given-a-list-containing-it-in-python) — Van Peer, Nov 07 '17 at 05:09

score 0 · Answer 1 · answered Nov 07 '17 at 05:24

0

You can do Like this

print(alist.index(value))

answered Nov 07 '17 at 05:24

sanket mokashi

The length of list is not fixed for me. How do I find index of value for nth value in array? – user2332713 Nov 07 '17 at 05:46
I don't understand! Is value the input? – sanket mokashi Nov 07 '17 at 06:38
Yes, value is the input – user2332713 Nov 07 '17 at 07:26
then , You can directly apply without comparison and use ** VALUE ERROR** exception to catch if value doesn't exist – sanket mokashi Nov 07 '17 at 07:31

score 0 · Answer 2 · answered Nov 07 '17 at 05:36

0

you can use .index(value) method to use it

value_index = alist.index(value)
print(value_index )

answered Nov 07 '17 at 05:36

iamsankalp89

2 Answers2