Is it possible to get all element in a list in python?

Question

Is there a function that returns the arrays that are in a list according to the search?

For example I want to get the list of tables containing the letter A

myLst = [[ABC], [BCV], [BAD]]
return [[ABC], [BAD]]

Do I have to make my own function ?

You can use a list comprehension, something like `return [x for x in myLst if 'A' in x]` — Patrick Haugh, Nov 07 '17 at 17:19
Possible duplicate of [Does Python have a string 'contains' substring method?](https://stackoverflow.com/questions/3437059/does-python-have-a-string-contains-substring-method) — KenHBS, Nov 07 '17 at 17:20
If the contents of the list are strings, use `''` when adding them in your question. — Dimitris Fasarakis Hilliard, Nov 07 '17 at 17:21

score 0 · Answer 1 · answered Nov 07 '17 at 17:53

0

Very possible, and simple, just do as follows

if x for x in list if 'a' in x:
     #Do something

It's simple list comprehension, I recommend reading Python MDN before starting to code

answered Nov 07 '17 at 17:53

Dwad

165
1
7

score 0 · Accepted Answer · answered Nov 08 '17 at 05:04

You can do in one line :

print([item for item in myLst for sub_item in item if 'A' in sub_item])

output:

[['ABC'], ['BAD']]

or as you said you want a function so here is the detailed solution :

def return_list(list_1):
    result=[]
    for item in list_1:
        if isinstance(item,list):
            for sub_item in item:
                if 'A' in sub_item:
                    result.append(item)
    return result

print(return_list(myLst))

Is it possible to get all element in a list in python?

2 Answers2