Python re.split

Question

For the following code,

import re
n = '.172..16.52.207,172.16.52.117'
s = re.split(',+|\.+',n)
print s

why is the first element of s a blank, i.e. '' ?

Because the first char is `.` that is matched with the splitting pattern. — Wiktor Stribiżew, Nov 08 '17 at 22:50
I would expect it to be 172, because I've specified the greedy + sign in the delimiter — Avishek Mondal, Nov 09 '17 at 00:07

score 0 · Answer 1 · edited Nov 08 '17 at 23:29

0

The first element is everything between the beginning of the string and the first .. There are no such characters, so it is ''. n[2] should be blank as well, because there is nothing between the second . and the third.

edited Nov 08 '17 at 23:29

the_storyteller

2,335
1
26
37

answered Nov 08 '17 at 22:52

Acccumulation

3,491
1
8
12

Is it at all possible to get the first element to be 172 using regex? – Avishek Mondal Nov 09 '17 at 00:10

Python re.split

1 Answers1