can a C++ function be defined using 'virtual inline'?

Question

I see a C++ function being defined as below:

int virtual inline fun()
{
   return xxx;
}

I wonder what it means? anyone can explain it?

Any function can be `inline`, but only non-static class member functions can be `virtual`. — user7860670, Nov 14 '17 at 09:54
C/C++ is undefined behaviour in C and C++, is the second lesson. — Bathsheba, Nov 14 '17 at 09:55
@AndrewGong There is C and there is C++, you can't mix them like that was one language C/C++, for example, your question don't make any sense in C, cause C don't have virtual key word. So please tag only one language in your question. Let other people decide if the question need more that one tag. — Stargateur, Nov 14 '17 at 11:23

score 0 · Answer 1 · answered Nov 14 '17 at 09:54

0

It simply means the code doesn't compile.

Only non-static methods can be virtual. In your example fun is a free function so virtual cannot be applied to it.

answered Nov 14 '17 at 09:54

bolov

but the function with this form does exit. and I can compile it in my vs2015 successfully. – JustinGong Nov 14 '17 at 11:14
@AndrewGong I highly doubt it. There is no way this can compile. – bolov Nov 14 '17 at 13:15
unless that is a method, but you haven't shown that in your post. In your post you showed a free function. That can't compile. If the code you are having and the code you are showing differ, that's another problem. And we can't start guessing what your real code is. – bolov Nov 14 '17 at 13:17

1 Answers1