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I am trying to print a decimal no. in following format : "#####+3.01" Case: There is a decimal no (let say 3.01 in this case). I have to print it with its sign +/- preceding with y no. of #, with some fix total width. (let say x = 10 in this case).

I tried do something like this :

   double no = 3.01;
   cout << setfill('#') << setw(10) ;
   cout << setiosflags(ios::showpos);
   cout << fixed << setprecision(2) << no << endl;

But i am getting followinfg output : 

    +#####3.01

Expected Output : 

    #####+3.01
Amit Anchalia
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    Possible duplicate of [std::ostringstream puts sign in wrong location?](https://stackoverflow.com/questions/46729847/stdostringstream-puts-sign-in-wrong-location) – Barmar Nov 18 '17 at 07:32

1 Answers1

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Your code gave me correct result. I am using a Linux machine.

Just in case it is a OS dependent problem, try this code:

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
    double no = 3.01;
    cout << setfill('#') << std::right<< setw(10) ;
    cout << setiosflags(ios::showpos);
    cout << fixed << setprecision(2) << no << endl;
}
Arash
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