Regex. Escape group?

Question

Is there any way to make something.+()[]* matching literally 'something.+()[]*'? I'm using regex builder so manual escaping is not allowed. Sure, i can add hardcoded checks if (char === '+') return '\+' but i'm looking for native solution or better way

UPD

I'm sorry. I forgot to add that matching should be in given order with moving forward but not back. So [+.] will not fit my requirements because it will match both +. and .+. I need only first case (In definition order)

score 0 · Answer 1 · answered Nov 22 '17 at 10:07

0

You don't need to escape them if within square brackets.. I just tested and works for me, but maybe not what you are looking for?

something[.+()[]]

answered Nov 22 '17 at 10:07

curv

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But that way, you'll also match `something[` or `something+`. – PJProudhon Nov 22 '17 at 10:08
Good point.. Trying to make the best of a bad situation here :-D. Anyway, he wants that right? – curv Nov 22 '17 at 10:09
I can't answer that, as there is no character class in the given pattern. – PJProudhon Nov 22 '17 at 10:22
I updated question – IC_ Nov 22 '17 at 10:25

Regex. Escape group?

1 Answers1