How to remove scientific notation from double for longest double value

Question

I am experiencing a problem in Double value manipulation.

Lets take,

Double d = new Double(123456789987654321123456789d);
System.out.println(d);

The output is :

1.2345678912345678E35

But I want,

123456789987654321123456789

The complete digit without any notation.

I have tried all permutation using BigDecimal, BigInteger and so and so.

Note: I want to populate into JSON so please don't suggest just a print statement.

I have already read :

Another side note: JSON does support scientific notation for numbers. — Haem, Dec 14 '17 at 09:17
I flagged this as a duplicate of one of the linked questions and then retracted; Because this number is of the order 2^86, the latter digits get truncated as a regular double. — Haem, Dec 14 '17 at 09:27

Youcef LAIDANI · Answer 1 · 2017-12-14T09:23:51.640

9

Try this BigDecimal::toPlainString:

BigDecimal d = new BigDecimal("123456789987654321123456789");
String result = d.toPlainString();

Output of d is :

123456789987654321123456789

To populated to JSon there are many ways, I'm not sure what you want exactly, but maybe this can help you How to create JSON Object using String?:

BigDecimal d = new BigDecimal("123456789987654321123456789");

JSONObject myObject = new JSONObject();
myObject.put("number", d.toPlainString());

edited Dec 14 '17 at 09:23

answered Dec 14 '17 at 09:13

Youcef LAIDANI

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*Note: I want to populate into JSon so please don't suggest just a print statement* – Lino Dec 14 '17 at 09:15
3

@Lino Using that value to populate JSON varies based on which JSON library the OP is using. Since the OP didn't share any information about that we can't give him a good answer on how to add this value to a JSON object. – BackSlash Dec 14 '17 at 09:19
@BackSlash You're right. @YCF_L Maybe you could provide also a solution that takes a `double` as an argument and not a `String`. As this is probably the use case the OP's having – Lino Dec 14 '17 at 09:19
@YCF_L not exactly, but still useful though! I meant the way to create a Bigdecimal from double – Lino Dec 14 '17 at 11:23
@Lino do you have a solution maybe? I don't see where is the problem with this way – Youcef LAIDANI Dec 14 '17 at 11:41
@YCF_L i mean that maybe the double is generated somehow: `double d = getDouble();` and then create from the variable `d` a `BigDecimal` instance – Lino Dec 14 '17 at 11:46
@BackSlash i am new to json , can you pls tell me what is 'JSON varies based on which JSON library the OP is using'? – Mohammed Rizwan Dec 21 '17 at 13:09
@YCF_L yeah that is good one, but the problem is i get this value as a function return type so if i convert also it is rounded off. so i cannot use this also. Double d = new Double(123456789987654321123456789d); BigDecimal bd = new BigDecimal(d); now again it is changed... – Mohammed Rizwan Dec 21 '17 at 13:14
@MohammedRizwan about JSON you can use [this](https://mvnrepository.com/artifact/org.json/json) or [this](https://mvnrepository.com/artifact/com.google.code.gson/gson) – Youcef LAIDANI Dec 21 '17 at 16:47

score 1 · Answer 2 · answered Dec 14 '17 at 09:37

1

You can try this

String str = String.format("%.0f", d);

Note that max digits a double can hold is ~17, so 123456789987654321123456789 will rounded

answered Dec 14 '17 at 09:37

Evgeniy Dorofeev

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How to remove scientific notation from double for longest double value

2 Answers2