Dealing with String array elements in Java

Question

So I have this particular code:

import java.util.*;

class insertWordInMiddle {
    public static void main(String[] args) {
        
        String s = "Python 3.0";
        String s_split[] = s.split(" ");

        String a = new String(s_split[0]);
        String b = new String(s_split[1]);

        String c = a + " Tutorial " + b;
        System.out.println(c);
        
    }
}

I was practising and I wanted to insert a word between two words (in the form of a string). It works, however I have yet other way of doing this but cannot get why it doesn't work:

import java.util.*;

class insertWordInMiddle {
    public static void main(String[] args) {
        
        String s = "Python 3.0";
        String s_split[] = s.split(" ");
        String final = s_split[0]+" Tutorial "+s_split[1];

        System.out.println(final);
    }
}

Error:

/home/reeshabh/Desktop/java practice/insertWordInMiddle.java:14:

error: not a statement

String final = s_split[0]+" Tutorial"+s_split[1];

`new String(s_split[0])` is unnecessary: `s_split[0]` is sufficient. — Andy Turner, Dec 15 '17 at 15:18

score 3 · Accepted Answer · answered Dec 15 '17 at 15:16

3

The simple answer is that final can't be the name of a variable. I can go into more detail if needed, but that's pretty much it. Try something else for your variable name.

answered Dec 15 '17 at 15:16

Francis Bartkowiak

1,374
2
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score 0 · Answer 2 · answered Dec 15 '17 at 15:18

0

final is a reserved keyword in Java. You can't name a variable final. Try renaming it to e.g. finalString.

Wikipedia has a list of all the reserved keywords.

answered Dec 15 '17 at 15:18

Nyubis

528
5
12

score 0 · Answer 3 · answered Dec 15 '17 at 15:20

final is a keyword. You can't use it as a variable name.

As per the building of strings: you could use StringBuilder, but for generating one string it's not really necessary. However, concatenating strings using the + operator will create copies of all strings involved and make baby cry when used within a loop.

When to use StringBuilder in Java

score 0 · Answer 4 · answered Dec 15 '17 at 15:21

You was just a bit unlucky - you used word that is reserved for other purposes in Java language. Take a look at this list, final is present here, so you can't name variables with words listed there: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/_keywords.html

Dealing with String array elements in Java

4 Answers4