How to initialize HashSet values by construction for Double?

Question

I am following link : How to initialize HashSet values by construction? and could be very silly question to ask, but I didn't make it working, please guide.

public class Demo {
    public static void main(String[] args) {
        Set<Double> tempSet = new HashSet<Double>();
        tempSet.add(11.0);
        tempSet.add(22.0);

        // Below both lines not working
        Set<Double> tempSet1 = new HashSet<Double>({11.0, 22.0});
        Set<Double> tempSet1 = new HashSet<Double>(){11.0, 22.0};
    }
}

`Set tempSet1 = new HashSet({11.0, 22.0});` doesn't compile. What kind of initialization are you trying to achieve? — Luiggi Mendoza, Jan 05 '18 at 17:29

score 1 · Answer 1 · answered Jan 05 '18 at 17:32

This statement doesn't make any sense: Set<Double> tempSet1 = new HashSet<Double>({11.0, 22.0}); If you're trying to initiallize them in just one line of code try this: Set<String> h = new HashSet<>(Arrays.asList(new Double[] {11.0,22.0})); Select as answer if it works! :D

score 1 · Answer 2 · answered Jan 05 '18 at 17:36

1

If you are using Java 9, Then

Set<Double> dblSet5 = Set.of(11.20, 2.0, 32.0, 56.0);

Or

Set<Double> dblSet5 = Set.of(<Array Of Double>);

answered Jan 05 '18 at 17:36

Ravi

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score 0 · Answer 3 · answered Jan 05 '18 at 17:31

0

Set<Double> tempSet1 = new Hashset<Double>(Arrays.asList(11.0,22.0));

answered Jan 05 '18 at 17:31

Rajan Singh

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7

score 0 · Answer 4 · answered Jan 05 '18 at 17:32

0

Based on the answers in that question, here are some examples:

//List initialization by using an array
Set<Double> h = new HashSet<>(Arrays.asList(11.0, 22.0));
//Java 8
Set<Double> set = Stream.of(11.0, 22.0).collect(Collectors.toSet());

answered Jan 05 '18 at 17:32

Luiggi Mendoza

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How to initialize HashSet values by construction for Double?

4 Answers4