preg_match if statement does only go into else part

Question

My code is as followed:

 public function validateTIME($param) 
    {
        $item = $param->Item;  
        $value = $item->configValue->TextBox->Text;

            if(preg_match('^([0-9]|0[0-9]|1[0-9]|2[0-3]):[0-5][0-9]$', "$value"))
            {
                echo 'nice';    
            }


            else{ echo "$value";
                  echo 'wrong';
                }   
    }

My question is why it does only go into the else part and not in the if one. The regex pattern is HH:MM (Hour=H Minute=M) and the pattern is ok.

If you do not get a warning on this you have to turn warnings and notices on while developing, or check your logs. This should throw a warning — Bart Haalstra, Jan 11 '18 at 14:06
i do have warnigs etc. on but it isnt an error it is only going to the else part — GermanMech, Jan 11 '18 at 14:07
This code of yours [will produce a warning](https://ideone.com/YhW1Vl). — Wiktor Stribiżew, Jan 11 '18 at 14:09
ok thats why im currently working on a project that i didnt developed so idk why it isnt throwing a warning — GermanMech, Jan 11 '18 at 14:10
but why this question gets downvoted isnt clear to me i think the question as a question is good. its a duplicate yeh but because i didnt get a warning i couldnt know that... — GermanMech, Jan 11 '18 at 14:12

score 0 · Accepted Answer · answered Jan 11 '18 at 14:04

0

use like this with //

if(preg_match('/^([0-9]|0[0-9]|1[0-9]|2[0-3]):[0-5][0-9]$/', "$value"))
            {
                echo 'abcdefg';    
            }

for more

answered Jan 11 '18 at 14:04

Umar Majeed

313
3
15

preg_match if statement does only go into else part

1 Answers1