python: compare sliced string to string with "is" equals False

Asked Jan 12 '18 at 19:49

Active Jan 12 '18 at 21:18

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Comparing a sliced string with more than 1 character to another string with is equals False. See Why does comparing strings in Python using either '==' or 'is' sometimes produce a different result?

But comparing only 1 character slices with is equals True. Why?

>>>> 'ab'[1:] is 'b'
True
>>>> 'abb'[1:] is 'bb'
False

edited Jan 12 '18 at 21:18

asked Jan 12 '18 at 19:49

masterfloda

https://stackoverflow.com/questions/13650293/understanding-pythons-is-operator – Mangohero1 Jan 12 '18 at 19:53
Ah, that makes sense. But why is the first equation `True`? – masterfloda Jan 12 '18 at 20:21
that, I don't know. might be that for single letters the difference is so small that the identities can overlap causing them to be the same. dunno. Perhaps Mr. Ryan can dedupe this based on this phenomenon! – Mangohero1 Jan 12 '18 at 20:50
I rephrased the question, so it focuses on the 1 character phenomen and could be de-duped. It would be interesting to see if anyone has an answer to that... – masterfloda Jan 12 '18 at 21:19
2

And I think I found the answer: https://en.wikipedia.org/wiki/String_interning – masterfloda Jan 12 '18 at 21:21
I believe that answer (interning) is already included in the linked duplicate. – Charles Duffy Jan 12 '18 at 21:41
Ah, true. In one of the comments further on the bottom. OK, so let's keep this question as a duplicate. Thanks everyone! – masterfloda Jan 12 '18 at 21:53

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