How do I get parameters from json

Question

From this json code

{
    "city": {
        "id": 1851632,
        "name": "Shuzenji",
        "coord": {
            "lon": 138.933334,
            "lat": 34.966671
        },
        "country": "JP",
        "cod": "200",
        "message": 0.0045,
        "cnt": 38,
        "list": [{
                "dt": 1406106000,
                "main": {
                    "temp": 298.77,
                    "temp_min": 298.77,
                    "temp_max": 298.774,
                    "pressure": 1005.93,
                    "sea_level": 1018.18,
                    "grnd_level": 1005.93,
                    "humidity": 87,
                    "temp_kf": 0.26
                },
                "weather": [{
                        "id": 804,
                        "main": "Clouds",
                        "description": "overcast clouds",
                        "icon": "04d"
                    }
                ],
                "clouds": {
                    "all": 88
                },
                "wind": {
                    "speed": 5.71,
                    "deg": 229.501
                },
                "sys": {
                    "pod": "d"
                },
                "dt_txt": "2014-07-23 09:00:00"
            }
        ]
    }

how do i get list.main.temp and list.weather.main which is in weather array?

My code to get list.main.tempis the following but it doesn't work:

JSONArray array = obj.getJSONArray("list");
 String temp = String.valueOf((Double) array.getJSONObject(i).getJSONObject("main").get("temp"));

Can anyone help me to fix the code and help me to get list.weather.main?

What do you mean by "but it doesn't work"? Are you getting any errors, exceptions, incorrect results? — Pshemo, Jan 13 '18 at 17:58
Possible duplicate: [How to parse JSON](https://stackoverflow.com/q/2591098) — Pshemo, Jan 13 '18 at 20:10

score 0 · Answer 1 · answered Jan 13 '18 at 17:55

0

I think this will help.

MyObject result = new ObjectMapper().readValue(json, MyObject.class);

where MyObject is the object you want to deserialize to. Then you can just call into the properties as you would normally in Java.

answered Jan 13 '18 at 17:55

Woody1193

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That's a lot of unnecessary overhead just to parse out a field – OneCricketeer Jan 13 '18 at 18:05
Well you wouldn't necessarily just be parsing out a field. Maybe in this particular instance that's all you want to do, but a lot of the time you want the entire object – Woody1193 Jan 13 '18 at 18:32

score 0 · Accepted Answer · answered Jan 13 '18 at 18:00

0

You cannot hop into the the middle of a JSON object.

The city element contains the list

obj.getJSONObject("city").getJSONArray("list");

You also need a loop around

array.getJSONObject(i)

You might want to look at Json-path to query data easier

answered Jan 13 '18 at 18:00

OneCricketeer

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Yes. Just look at the indentation – OneCricketeer Jan 13 '18 at 18:51
Ok but I still can't figure out how can I get main which is inside weather array. – Daniele Jan 13 '18 at 19:17
1

Start from the top... Look at the different bracket types, and use arrays or objects accordingly `GetArray("list")...GetObject(0)...GetArray("main")...GetObject(0)...Get("weather")` – OneCricketeer Jan 14 '18 at 03:41

How do I get parameters from json

2 Answers2