Jquery get the custom response content when I do an ajax and return an error

Question

I am doing a classing ajax ger request:

$.get('/ajax').done(function(data){
   //handle data on success
}).fail(function(jqXHR,status,errorThrown){
    if(jqXHR.status===500){
       //Handle response there
    }
})

I want somehow to be able to get the custom response when my endpoint to ajax request returns error 500.

Note on the duplicate `error` is your proper `fail` with the same parameters passed back. jqXHR here http://api.jquery.com/jQuery.ajax/#jqXHR — Mark Schultheiss, Jan 20 '18 at 20:28

nitte93 · Answer 1 · 2018-01-20T19:51:04.550

1

I don't think $.get has .error method. See here, http://api.jquery.com/jQuery.get/#jqxhr-object

Instead, you need to handle the error inside the .fail

If you really want to handle using .error then do $.ajax instead

edited Jan 20 '18 at 19:51

answered Jan 20 '18 at 19:49

nitte93

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That's correct it was a typo and I fixed my question – Dimitrios Desyllas Jan 20 '18 at 19:50

Dimitrios Desyllas · Answer 2 · 2018-01-20T20:06:18.897

0

Based on Why is jqXHR.responseText returning a string instead of a JSON object? you can get the response data when an error occurs using:

$.get('/ajax').done(function(data){
   //handle data on success
}).fail(function(jqXHR,status,errorThrown){
    if(jqXHR.status===500 && jqXHR.responseText){
      console.err(jqXHR.responseText);
    }
});

edited Jan 20 '18 at 20:06

answered Jan 20 '18 at 19:48

Dimitrios Desyllas

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what is `jxqr`, it is not defined anywhere? – nitte93 Jan 20 '18 at 19:55
fixed the mentioned typo – Dimitrios Desyllas Jan 20 '18 at 20:06

Jquery get the custom response content when I do an ajax and return an error

2 Answers2