Php function including if statements and return

Question

Why do I get error in syntax from the code below:

<?php>
function wpai_package($price, $pack) {
    if($pack!=' '){
        return ($pack * $price);
    } else {
        return($price)
    }
}
?>

Syntax error unexpected'}' on line 8

I want to say if the pack IS NOT EMPTY (null) then price x pack otherwise price.

Thanks

Possible duplicate of [PHP Parse/Syntax Errors; and How to solve them?](https://stackoverflow.com/questions/18050071/php-parse-syntax-errors-and-how-to-solve-them) — Nigel Ren, Jan 23 '18 at 11:20

AmalJo · Answer 1 · 2018-01-23T11:10:25.483

1

you missed an ; near return

 <?php
function wpai_package($price, $pack) {
   if(!empty($pack)){
     return ($pack * $price);
   } else {
     return($price);

   }
}
?>

edited Jan 23 '18 at 11:10

answered Jan 23 '18 at 11:00

AmalJo

106
9

This one gives no error but all the prices where the pack is null come 0 – babi mc Jan 23 '18 at 11:06
could you share more info – AmalJo Jan 23 '18 at 11:07

TarangP · Accepted Answer · 2018-01-23T11:07:37.760

0

Change Your Code To

<?php


function wpai_package($price, $pack) {

    if(!empty($pack))
    {
        return ($pack * $price);
    } else {
        return $price;
    }
}

wpai_package(2,45);

Live Demo

And Also You Should Have to LEarn Return At here http://php.net/manual/en/function.return.php

edited Jan 23 '18 at 11:07

answered Jan 23 '18 at 11:00

TarangP

2,711
5
20
41

This one gives no error but all the prices where the pack is null come 0 – babi mc Jan 23 '18 at 11:04
So what would you expect ? – TarangP Jan 23 '18 at 11:06

score 0 · Answer 3 · answered Jan 23 '18 at 11:17

0

In the first line you added a > after <?php which has to be removed.

In line 7 the semicolon is missing at the end of the line.

answered Jan 23 '18 at 11:17

Rico

107
6

Php function including if statements and return

3 Answers3