input in mapping dictionary python

Question

I'm trying to implement dict in python.

This code work perfectly:

  def numbers_to_strings(argument):
    switcher = {
        0: "zero",
        1: "one",
        2: "two",
    }
    return switcher.get(argument, "nothing")

print (numbers_to_strings(0))

In this case the output is "zero".

But when I try to implement the one by input , I always get "nothing" :

def numbers_to_strings(argument):
    switcher = {
        0: "zero",
        1: "one",
        2: "two",
    }
    return switcher.get(argument, "nothing")

print ("To write a number: ")
number = input ()
print (numbers_to_strings(number))

Best Regards.

Possible duplicate of [How can I read inputs as integers?](https://stackoverflow.com/questions/20449427/how-can-i-read-inputs-as-integers) — miradulo, Feb 02 '18 at 17:01
Version of python matters. input works differently in 2.x vs 3.x: https://stackoverflow.com/questions/4915361/whats-the-difference-between-raw-input-and-input-in-python3-x — Stucco, Feb 02 '18 at 17:01

score 2 · Answer 1 · answered Feb 02 '18 at 16:59

2

As pointed out by Daniel Roseman, input returns a string so simply change this line:

number = input ()

to: number = int(input())

answered Feb 02 '18 at 16:59

gaw89

1,018
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19

score 0 · Accepted Answer · answered Feb 02 '18 at 16:59

0

The input is saving the number you enter as string. You need to parse number to integer before you call numbers_to_strings

answered Feb 02 '18 at 16:59

DobromirM

2,017
2
20
29

input in mapping dictionary python

2 Answers2