Match only first and last 4 numbers using regex

Question

So i want to match the first number and the last four numbers using regex.

I am able to get the last 4 numbers using \d(?=\d{4}) but unable to get the first and last four numbers together. Tried multiple combinations.

Try [`\b\d(?=\d*(?:\D*\d+){0,3}\D*$)`](https://regex101.com/r/rDMYmt/2). BTW, by "numbers", do you mean *integer* numbers? — Wiktor Stribiżew, Feb 08 '18 at 12:37

score 0 · Answer 1 · answered Feb 08 '18 at 12:54

String with Numbers and other characters

^.*?(\d).*(\d).*?(\d).*?(\d).*?(\d).*?$

See the demo

Captures the first number in the string, and then captures the last 4 numbers (all individually, allowing any characters in between).

Breakdown:

^.*? - Lazily match everything
(\d) - until it encounters and captures the first number
.* - Greedily match everything
(\d).*?(\d).*?(\d).*?(\d).*?$ - until it encounters the last 4 numbers with anything in between them, capturing only the numbers. ($ for the end of the string)

Just Numbers

If instead you want to capture these with numbers only:

^(\d)\d+(\d{4})$

See the demo

1 Answers1