URL error char set?

Question

I tried to call a custom url using this code below:

let myurl = "https://myserver.com/call?a|b|c"
let converted = URL(string: myurl)
print(converted)

But what I'm getting as result in converted is just "nil".

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I'm pretty sure this is because of the wrong characters set in relation to the URL() class.

After some research all I got so far is this outdated Swift code:

var myurl = "https://myserver.com/call?a|b|c"
var newurl = myurl.stringByAddingPercentEncodingWithAllowedCharacters(.URLHostAllowedCharacterSet())
print(newurl)

But it doesn't seems working this way.

How can I achieve to avoid the "nil" result using (in my case) Swift 4?

Answer 1

Found the solution on my own:

let myurl = "https://myserver.com/call?a|b|c"
let converted = URL(string: myurl.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)!)

print(converted!)

The new function is called addingPercentEncoding & I have to call it with the urlQueryAllowed property.

The urlQueryAllowed charset adds some characters like this to the url encoding: "!*'();:@&=+$,/?%#[]|"

Volià!