Multidimensional Array : index out of range

Question

I'm learning python and wanted to use multidimensional array like we use in c and researched about it and have written the code but stuck at one place and I don't understand why the error is occurring.

My Code:-

a=[]
i=0
for record in tablerows: 
    a.append([])
    rowcells=record.findAll('td')
    for data in rowcells[1:4]:
        a[i].append(data.text)
        i=i+1
        print(a)

Error:

a[i].append(data.text) IndexError: list index out of range.

On second iteration.
Can you please guide me...?
And I'm doing it right or is there a better way of doing it....?

Possible duplicate of [Getting a default value on index out of range in Python](https://stackoverflow.com/questions/2574636/getting-a-default-value-on-index-out-of-range-in-python) — l'L'l, Feb 25 '18 at 07:30
@Javier Lim here is the assignment for tablerows variable. tablerows=tbody.findAll('tr') and for rowcells the assignment is done itself in for loop which is in the line rowcells=record.findAll('td') — ronaldo, Feb 25 '18 at 07:38
@Javir Lim the assignment for both tablerows and rowcells is correct i have checked it.Only the problem is in the 2d array — ronaldo, Feb 25 '18 at 07:39
tbody is actually an html table and record is a row in the table — ronaldo, Feb 25 '18 at 07:40
I wrote the code without the array first and was working fine — ronaldo, Feb 25 '18 at 07:43
Ok, try shifting i = i + 1 out of the second loop, into the first after the second loop. — Javier Lim, Feb 25 '18 at 07:43

score 1 · Accepted Answer · answered Feb 25 '18 at 07:49

1

Shift i = i + 1 out of the second loop, like this.

a=[]
i=0
for record in tablerows: 
    a.append([])
    rowcells=record.findAll('td')
    for data in rowcells[1:4]:
        a[i].append(data.text)
        print(a)
    i=i+1

answered Feb 25 '18 at 07:49

Javier Lim

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Multidimensional Array : index out of range

1 Answers1