Regex to replace specific expression

Question

I have an regex to replace some input, this is the input {{number}}-{{$index}}

And i want transform to result = ["{{number}}", "{{$index}}"]

I trying with this regex ({{).*?(}}) but don't give me what i'm expect

What language are you using? What is the replacement string you're using? — Barmar, Feb 27 '18 at 18:07
Are `number` and `$index` literal strings, or are they variable? — Barmar, Feb 27 '18 at 18:07
From the way this is worded, it looks like you could do `result = input.split("-")` — Dan Prince, Feb 27 '18 at 18:11
I'm just try to using a regex to modify the variable content, they come with this symbols, i'm sorry they are not variables, they are a literal string and i want apply this regex to transform — , Feb 27 '18 at 18:12
@JoãoVictorCanabarro can you **explain your intent**? It's not clear what you're trying to accomplish. Take a step back and read your question as if you have no preconceived knowledge about the task at hand. — ctwheels, Feb 27 '18 at 18:15
The string `{{number}}-{{$index}}` comes for a outside function, but between `{{number}}` and ` {{$index}}` could has anything and i want remove this and just take this 2 parts of the text, just only that — , Feb 27 '18 at 18:19
Just match on [`{{[^{}]*}}`](https://regex101.com/r/nxl5GC/1) and if you want to match single `{` or `}` inside those brackets use [`{{(?:(?!{{|}}).)*}}`](https://regex101.com/r/nxl5GC/2) — ctwheels, Feb 27 '18 at 18:20
@ctwheels Could you please add this to the answer of the post — , Feb 27 '18 at 18:24

score 0 · Accepted Answer · answered Feb 27 '18 at 18:29

To extract all {{x}} where x can be any character except { or } you can use the following:

{{[^{}]*}}

Similarly, the following regex does the same as the previous but allows single { and }, but not double {{ or }}:

{{(?:(?!{{|}}).)*}}

{{ Match this literally
(?:(?!{{|}}).)* Match any character any number of times except where {{ or }} exists. This is called a tempered greedy token.
}} Match this literally

For a very slight performance gain, you can substitute each instance of {{ for {{2} and each instance of }} for }{2}.

You may add `(` and `)` for grouping – StyleSh1t Feb 27 '18 at 18:44 — StyleSh1t, Feb 27 '18 at 18:44

1 Answers1