read all files in a subfolder python

Question

I have a folder structure as

>root
  > foldername1
    > subfoldername1
    > subfoldername2
    > subfoldername3
  > foldername2
    > subfoldername1
    > subfoldername2
    > subfoldername3
  > foldername3
    > subfoldername1
    > subfoldername2
    > subfoldername3

I would like to list all the file contained in the 'subfoldername3' of 'foldername2'

I approached the problem as follow, but since I have an incredible number of folders, subfolders, and files it takes forever to come to a conclusion.... is there a fastest way to do the same?

all_folders = [x[0] for x in walk(root)]
sub_folder = [s for s in all_folders if 'foldername2' in s]
matching_sub_path = [s for s in sub_folder if 'subfoldername3' in s]

matching_sub_path =
//root//foldername2//subfoldername3

if you know the folder name, directly use it in `os.listdir()` — Rahul, Mar 06 '18 at 08:32
I know that the root folder contains the string "foldername2" and that the subfolder contains the string "subfoldername3", but I am not sure of the entire names — gabboshow, Mar 06 '18 at 08:35
ok. Then your way is the right way. os.listdir will be faster. — Rahul, Mar 06 '18 at 08:37
Sorry, I didn't notice it since the `os.` part was missing. Then I don't think there is going to be a faster way/ — ChatterOne, Mar 06 '18 at 08:39
have a look at [glob](https://docs.python.org/2/library/glob.html) I believe it does what you want — ArnJac, Mar 06 '18 at 08:46
Possible duplicate of [How do I list all files of a directory?](https://stackoverflow.com/questions/3207219/how-do-i-list-all-files-of-a-directory) — Maximilian Peters, Mar 06 '18 at 09:02

score 0 · Accepted Answer · answered Mar 06 '18 at 09:00

I think os.walk will list all directory recursively.

for you case try this if it suits your need.

all_folders = [x[0] for x in walk(root)]

all_files = [os.listdir(dir_path)
             for dir_pathin all_folder
                 if "subfoldername3" and "foldername2" in dir_path]

read all files in a subfolder python

1 Answers1