remove leading 0s with stringr in R

Question

I have the following data

I would like to remove the leading 0s so the data would like like the following

score 34 · Accepted Answer · answered Mar 09 '18 at 05:05

34

Using the new str_remove function in stringr:

id = str_remove(id, "^0+")

answered Mar 09 '18 at 05:05

Marius

1

For posterity, I had to update my `stringr` version to `1.3.0` – Alex Mar 09 '18 at 05:35

score 13 · Answer 2 · answered Mar 09 '18 at 05:10

13

We can just convert to numeric

as.numeric(df1$id)
[#1]    1   10   22 7432

If we require a character class output, str_replace from stringr can be used

library(stringr)
str_replace(df1$id, "^0+" ,"")
#[1] "1"    "10"   "22"   "7432"

answered Mar 09 '18 at 05:10

akrun

What does the "^0+" part mean? – Basil Feb 08 '21 at 10:52
1

@Basil The `+` implies one or more, so if the 0 is prefix, it would be one or more zeros and the `^` suggest the start of the string. Therefore, the pattern checked is one or more zeros as the beginning of a string – akrun Feb 08 '21 at 16:16

score 12 · Answer 3 · answered Mar 09 '18 at 05:04

12

Here is a base R option using sub:

id <- sub("^0+", "", id)
id

[1] "1"    "10"   "22"   "7432"

Demo

answered Mar 09 '18 at 05:04

Tim Biegeleisen