Compare a string to a string an array ignoring the case

Question

I am wanting to compare a string called itemToReplace to one in an array but ignoring the case (if it's a capital letter or lower case).

Here is the code:

itemToReplace = input("Choose an item to replace: ")
if itemToReplace in self._inventory:
    # do something...

And when I do this, if the user types in something like "sWord" instead of "Sword", it won't work. So does anyone know how to do this?

Thanks.

simply add either `.upper()` or `.lower()` to the end of the input and it will change the case so you can deal with it easier — johnashu, Mar 09 '18 at 15:01
Do you want to ignore the case and other extra capitalized letters in the string? If so, then use .lower() method on the string you want. — R.R.C., Mar 09 '18 at 15:04

score 0 · Answer 1 · answered Mar 09 '18 at 15:02

0

Change the case of the entire input by doing.

itemToReplace = input("Choose an item to replace: ").upper() #Uppercase

or

itemToReplace = input("Choose an item to replace: ").lower() #Lowercase

answered Mar 09 '18 at 15:02

johnashu

score 0 · Accepted Answer · answered Mar 09 '18 at 15:03

0

This should help.

import string
print 'sWord'.lower() in map(string.lower, ['Sword'])

Output:

True

Convert the input to lower case
use map method to convert all string elements in list to lower and the use in .

answered Mar 09 '18 at 15:03

Rakesh

he needs to change the case of a single string input, not a list.. Ideal for a list but a little too much for a single string..of course if the `_inventory` is full of mixed case strings then this will be ideal! – johnashu Mar 09 '18 at 15:09

2 Answers2