Gulp is creating a directory instead of a file

Question

I want gulp to spit out a style.min.css:

// Minify
gulp.task('minify-css', function () {
    gulp.src('css/style.css')
        .pipe(cleanCSS())
        .pipe(gulp.dest('css/style.min.css'))
});

it is minifying the .css but instead is creating a directory with a style.css in it:

css/style.min.css/style.css

Any help? Thanks.

score 5 · Accepted Answer · edited Mar 13 '18 at 21:04

5

gulp.dest writes to directories. You should add a rename step before piping to gulp.dest.

.pipe(rename('style.min.css'))
.pipe(gulp.dest('css/'))

You should be able to use the gulp-rename module for this.

edited Mar 13 '18 at 21:04

pushkin

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answered Mar 13 '18 at 20:58

dudeman

503
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11

Got it. I was telling gulp to create a directory in dest named style.min.css. Thank you very much! – Labanino Mar 13 '18 at 21:12

Gulp is creating a directory instead of a file

1 Answers1