PHP checkbox echo errors syntax error

Question

I get a Parse error: syntax error when I echo 2 checkbox rows. I think there is something with the 2nd tag because the first checkbox: FILM DRAAI DAGEN. echo's right.

 <tr>
    <td>
        <?php echo 'Film draai dagen: ';?>
    </td>
    <td>
<?php
if(!empty($_POST['draaidag']))
{
    foreach($_POST['draaidag']as$check)
    {
        echo " ".$check;
        $draaidag = " ".$check;
    }
?>
    </td>
</tr>

<tr>
    <td>
        <?php echo 'Film tijd dagen: ';?>
    </td>
    <td>
<?php
if(!empty($_POST['tijddag']))
{
    foreach($_POST['tijddag']as$check)
    {
        echo " ".$check;
        $tijddag = " ".$check;
    }
?>
    </td>
</tr>

Please accept if it works :) https://stackoverflow.com/help/someone-answers — Brian Patterson, Mar 17 '18 at 00:42
@BrianPatterson and riggs thx for the help I accepted the question — Kapitein Plus, Mar 17 '18 at 00:47

score -1 · Accepted Answer · edited Mar 17 '18 at 00:42

-1

Syntax error means your code has errors. In this case you did not close the if statement. Simply add a curly brace at the end before your closing tag.

<td>
<?php
    if(!empty($_POST['draaidag']))
    {
        foreach($_POST['draaidag']as$check)
        {
            echo " ".$check;
            $draaidag = " ".$check;
        }
    } //<--- this guy
?>
</td>

edited Mar 17 '18 at 00:42

RiggsFolly

93,638
21
103
149

answered Mar 17 '18 at 00:39

Brian Patterson

1,615
2
15
31

PHP checkbox echo errors syntax error

1 Answers1