I expect the following code to compile and print Foo(6) as the value of b, owning the reference to a is dropped after the match block.
It seems related to this compiler error:
error[E0502]: cannot borrow `a` as immutable because it is also borrowed as mutable
  --> src/main.rs:26:22
   |
13 |     let b = get_foo(&mut a);
   |                          - mutable borrow occurs here
...
26 |     println!("{:?}", a);
   |                      ^ immutable borrow occurs here
27 | }
   | - mutable borrow ends here
Dropping the value of b doesn't work either, because it is partially moved:
error[E0382]: use of partially moved value: `b`
  --> src/main.rs:24:10
   |
18 |         Some(value) => *value = y,
   |              ----- value moved here
...
24 |     drop(b);
   |          ^ value used here after move
   |
   = note: move occurs because `(b:std::prelude::v1::Some).0` has type `&mut u32`, which does not implement the `Copy` trait
Is there a better way to fix this rather than putting lines let b and match b into an inner block? That just looks weird and ugly.
Shouldn't the compiler understand that the reference is dropped, and be able to compile that code?
#[derive(Debug)]
struct Foo(u32);
fn get_foo(bar: &mut Foo) -> Option<&mut u32> {
    Some(&mut bar.0)
}
pub fn test() {
    let mut x = 5;
    let mut y = 6;
    let mut a = Foo(x);
    // {
    
    let b = get_foo(&mut a);
    match b {
        Some(value) => *value = y,
        _ => (),
    }
    
    // }
    //    drop(b);
    println!("{:?}", a);
}