How to convert string consisted of several numbers with a space into a list of integer values of that same string?

Question

I have a string that consists of numbers with a space.

myString = "3 45 12"

I want to make a list of integer values derived from that string, ex:

myList = [3, 45, 12]

Please refer https://stackoverflow.com/questions/642154/how-to-convert-strings-into-integers-in-python — DAIRAV, Mar 27 '18 at 06:52
A simple 1 line solution: `myList = [int(i) for i in myString.split()]` — ScottMcC, Mar 27 '18 at 06:59

score 3 · Accepted Answer · answered Mar 27 '18 at 06:53

3

Try this:

myString = "3 45 12"
numericdata = myString.split(' ')
numbers = []

for i in numericdata:
    numbers.append(int(i))

print(numbers)

answered Mar 27 '18 at 06:53

it works, thank you! – bit_scientist Mar 27 '18 at 07:13
@Sohib Welcome! and if it works than please accept the answer! Thankyou! :) – Abdullah Ahmed Ghaznavi Mar 27 '18 at 07:14
what if I had negative numbers in my string as well? I am receiving this error: `numbers.append(int(i)) ValueError: invalid literal for int() with base 10: 'f'` I think it is related to negative integers in the string. – bit_scientist Mar 27 '18 at 09:39
i think it doesn't matter if you have negative numbers to it will works fine unless you have a space in negative sign. are you using negative numbers like this : `- 2` or like this: `-2` – Abdullah Ahmed Ghaznavi Mar 27 '18 at 09:47
I am using as -2. Actually this a part of a code I am writing, your code is working separately, but when I insert inside another code, I have an error as I commented above. – bit_scientist Mar 27 '18 at 09:50
Let me post it as a new question in a while – bit_scientist Mar 27 '18 at 09:52
@Sohib Yeah it will be great if you do that – Abdullah Ahmed Ghaznavi Mar 27 '18 at 09:52
please refer to [here](https://stackoverflow.com/questions/49510009/valueerror-invalid-literal-for-int-with-base-10-f) – bit_scientist Mar 27 '18 at 10:07

1 Answers1