Set value of dynamic var in bash

Question

I have the following case:

A=1
echo $A # output 1
B='A'
echo $B  # output A
echo "\$$B=2" # output $A=2
echo "\$$B=2" | eval # this won't set $A to 2

I'd like $A to get 2 as value.

Why are you piping into `eval`. Did you mean `eval "\$$B=2"`? — Mad Physicist, Mar 29 '18 at 05:29
@MadPhysicist fixed my question. `eval "\$$B=2"` won't set $A — darioguarascio, Mar 29 '18 at 05:30
@codeforester thanks it was what i was looking for, just with no arrays — darioguarascio, Mar 29 '18 at 05:32

score 0 · Answer 1 · answered Mar 29 '18 at 05:34

0

Found a solution using declare ( Dynamic variable names in Bash )

B='A'
declare "$B=2"
echo $A # output 2

answered Mar 29 '18 at 05:34

darioguarascio

1 Answers1