Sort an object literal on its attribute value

Question

Below is my input, I would be looping through each of this element and sending each element to another function.

 distinctParameterList  =  [{
        careerGroupLevel: 'Analyst',
        careerGroupCode: 130,
        m06: 83,
        m05: 82,
        m08: 85,
        fymcl: 'FY18|PromotionsOut|AN-10000100:CL 2',
        m07: 84,
        m09: 86,
        intersectionId: '54697113|India|520|N'
    },
     {
        careerGroupLevel: 'Analyst',
        careerGroupCode: 130,
        m06: 95,
        m05: 94,
        m08: 97,
        fymcl: 'FY18|PromotionsOut|AN-10000110:CL 2',
        m07: 96,
        m09: 98,
        intersectionId: '54697113|India|520|N'
    },
     {
        careerGroupLevel: 'Analyst',
        careerGroupCode: 130,
        m06: 22,
        m05: 21,
        m08: 24,
        fymcl: 'FY17|PromotionsOut|AN-10000100:CL 2',
        m07: 23,
        m09: 25,
        intersectionId: '54697113|India|520|N'
    },
     {
        careerGroupLevel: 'Analyst',
        careerGroupCode: 130,
        m06: 42,
        m05: 41,
        m08: 44,
        fymcl: 'FY17|PromotionsOut|AN-10000110:CL 4',
        m07: 43,
        m09: 45,
        intersectionId: '54697113|India|520|N'
    }]

I am also calculating a value "calcCareerId " below :

let calcCareerId = fymclData.split("-")[1].split(":")[0];

Now i want to sort this structure on the basis of the "calcCareerId " value in fymcl attribute, so that i can get all the "10000100" values first and then "10000110".

That is a JavaScript object literal. JSON is a `string`. – Apr 03 '18 at 19:21 — , Apr 03 '18 at 19:21

Huy Nguyen · Accepted Answer · 2018-04-03T19:38:53.077

0

Define the function:

let calcCareerId = fymclData => fymclData.split("-")[1].split(":")[0];

You can use lodash's sortBy function to sort in lexicographically ascending order. If you want descending order, just call .reverse on the result.

const result = _.sortBy(distinctParameterList, ({fymcl}) => calcCareerId(fymcl));

or use the native sort:

const result = distinctParameterList.sort((a, b) => {
  const valueA = calcCareerId(a.fymcl);
  const valueB = calcCareerId(b.fymcl);
  return (valueA === valueB) ? 0 : (valueA < valueB ? 1 : -1)
})

Note that the native sort mutates the array and is not stable.

edited Apr 03 '18 at 19:38

answered Apr 03 '18 at 19:29

Huy Nguyen

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Why resort to a library instead of using native `Array.prototype.sort()`? – connexo Apr 03 '18 at 19:33
But "calcCareerId" is only available when iam looping through the array. But the requirement is that before triggerring that loop, i need the array sorted by "10000100" etc i.e. the "fymcl" attribute value – rp4361 Apr 03 '18 at 19:38
@Rishabh Then define `calcCareerId` at the same level as `distinctParameterList`. – Huy Nguyen Apr 03 '18 at 19:40
but calcCareerId can only be calculated when i loop in through each element of this array and then locate the fymcl attribute and then split it. – rp4361 Apr 03 '18 at 19:45
lets not confuse with calcCareerId. What i need is the array should be sorted on the basis of the value in fymcl attribute – rp4361 Apr 03 '18 at 19:46
const result = distList.sort((a, b) => { const valueA = (a.fymcl.split("-")[1].split(":")[0]); const valueB = (b.fymcl.split("-")[1].split(":")[0]); return (valueA === valueB) ? 0 : (valueA < valueB ? 1 : -1) }) // this is now sorting – rp4361 Apr 03 '18 at 19:54
is there a way to use sort in a callback ? – rp4361 Apr 03 '18 at 19:55

Sort an object literal on its attribute value

1 Answers1