check every element of an array

Question

What is the most efficient way to check a certain condition on every element of an array and return false if one or more elements do not meet the condition, for example, I have this array for example

arr = ["foo","azeaze", "wazeazerar"]
    for(var ar in arr){
      if(ar.length > 5){
        console.log(false)
      }else{
        console.log(true)
      } 
    }

as you can see it return true even if the element "foo" length is not greater than 5

Have you tried debugging this on your own to see what `ar` contains? — Nico Haase, Apr 08 '18 at 08:28
It marked as duplicated even if it dosent answear my question — arkahn jihu, Apr 08 '18 at 08:42
Sure, it does: you should not use `for... in` if you want to iterate over the values of an array — Nico Haase, Apr 08 '18 at 09:23

Abslen Char · Accepted Answer · 2018-04-08T08:34:30.653

8

You can use Array.prototype.every() in a one line function

arr = ["foo","azeaze", "wazeazerar"]

const isittrue = currentval =>  currentval.length > 2

console.log(arr.every(isittrue));

 arr = ["foo","azeaze", "wazeazerar"]
    console.log(arr.every(elem => elem.length >= 5))

edited Apr 08 '18 at 08:34

answered Apr 08 '18 at 08:26

Abslen Char

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Thank you sir , thankfully you did answear my question before the admin mark it as duplicated because i didnt understund why he mark it as duplicated even if it wasnt what I was asking – arkahn jihu Apr 08 '18 at 08:43

check every element of an array

1 Answers1