how to out put Php variable in html element attribute in laravel

Question

i have the following code

@php

    $id = some integer
    echo  '<'.input type="hidden" class="id" name="id" value="$id". '>'
@endphp

how can i use this $id variable inside html element attribute

it produce the following error

Parse error: syntax error, unexpected '$id' (T_VARIABLE), expecting ',' or ';' (View: C:\xampp\htdocs\blog\resources\views\post\userposts.blade.php)

Your code is so full of parsing errors, that even when you fix that first one at least three others should occur one after another. This does not even look related to PHP code. Are you sure that this is not some template engine you are working with? — feeela, Apr 12 '18 at 08:09

score 4 · Answer 1 · answered Apr 12 '18 at 08:08

4

You already are in a blade template, just use blade and its syntax:

@php
 $id = whatever you need
@endphp

<input type="hidden" class="id" name="id" value="{{ $id }}">

As you see you can use your variables with the special quotation {{ $var }}

answered Apr 12 '18 at 08:08

javier_domenech

this doesn't work it produce undefined variable error – Hidayat ullah Apr 12 '18 at 08:11
it should, check your variable definition, also, I suggest you defining it on your controller and passing it to the view, instead of defining on the view itself – javier_domenech Apr 12 '18 at 08:13
i need it in view – Hidayat ullah Apr 12 '18 at 08:19
Then check the syntax on your definition, pay special attention to colon, semicolons. – javier_domenech Apr 12 '18 at 08:24

score 1 · Answer 2 · answered Apr 12 '18 at 08:32

1

There are a lot of ways to do this. You just need to search it.

@php
   $id = some integer
@endphp

<input type="hidden" class="id" name="id" value="<?php echo $id; ?>">

or

@php

$id = some integer
echo  '<input type="hidden" class="id" name="id" value="'.$id.'">';

@endphp

or

@php
   $id = some integer
@endphp

<input type="hidden" class="id" name="id" value="{{ $id }}">

I suggest to call the $id from controller or the value of $id.

answered Apr 12 '18 at 08:32

Onitech

but this variable is not accessible out side of the ending tag of php – Hidayat ullah Apr 12 '18 at 08:56
Try using "". – Onitech Apr 12 '18 at 09:05

score 0 · Answer 3 · answered Apr 12 '18 at 08:07

0

You forget to use semicolon at the end of the line:

$id = 111;// some integer

answered Apr 12 '18 at 08:07

Pavel

score 0 · Answer 4 · answered Apr 12 '18 at 08:07

0

Your concatenation is wrong, you should pay attention to what you wrote, here is the good way of making it work:

$id = 5;
echo  '<input type="hidden" class="id" name="id" value="' . $id . '">';

answered Apr 12 '18 at 08:07

Hammerbot

score 0 · Answer 5 · answered Apr 12 '18 at 08:21

0

Either of these should work ..

<input type="hidden" class="id" name="id" value="<?=echo $id;?>"

OR

 <input type="hidden" class="id" name="id" value="<?php echo $id;?>"

answered Apr 12 '18 at 08:21

Paddy Popeye

this produce the following out put is value of id " – Hidayat ullah Apr 12 '18 at 08:24
that woould indicate that the PHP is not being loaded at all. – Paddy Popeye Apr 12 '18 at 08:33
if you leave only "@php $id=someInteger; echo $id; @endphp" and itt displays nothing then then php engine is not even parsing the doc – Paddy Popeye Apr 12 '18 at 08:38

5 Answers5