How to get just specified numbers from a large number?

Question

How can I get specified number?

For example, the number that a user enters is 4568962358.

I want to save the "96" in a variable; how do I get just the 96 or 23?

This is the real problem:

An important shipping company is making the annual inventory of the goods they have in their warehouse, for which they have implemented a system of codes that are assigned to each good that is in said warehouse. This code, which consists of 16 digits, contains the following information: unique number, indicator of whether it is fragile or not, place of origin of the property and expiration date of the property.   The assigned code structure is UUUFPPPPDDMMAAAA where:

• UUU: unique number of the good.
• F: digit that indicates if the good is fragile or not. If it is 0 it means that it is fragile.
• PPPP: ASCII codes of the two letters that identify the country of origin of the good.
• DD: Good's due date.
• MM: Month of the expiration of the good.
• AAAA: Year of expiration of the good.

You are asked to create a C ++ program that receives the assigned code as data and then prints the following data as shown in the example.

Enter the code: 1120677212042015

Then the program must print: Unique number: 112. Fragile(N: No; S: Yes): S . Country of origin: CH . Day, month and year of expiration: 04-12-2015 . Well it is outdated to date (N : No; S: Yes): S.

In the solution of the problem you will not be able to make use of selective structures.

Version 1

#include "stdafx.h"
#include "conio.h"
#include "iostream"


using namespace System;
using namespace std;

int main()
{
    int code;
    int UUU;
    int F;
    int PP1,PP2;
    int DD;
    int MM;
    int AAAA;


    cout << "Enter the code: "; cin >> code; // 1120677212042015

    // ...code needed here

    UUU = int(code / 10000000000000);

    cout << "\nRESULTS" << endl;
    cout << "\nUnique number: " << UUU << endl; // prints 112

    _getch();
    return 0;
}

Version 2

I'm not able to do the next parts; please help!

#include "stdafx.h"
#include "conio.h"
#include "iostream"

using namespace System;
using namespace std;

int main()
{
    double code;
    double UUU;
    double F;
    double PP1,PP2;
    double DD;
    double MM;
    double AAAA;


    cout << "Enter the code: "; cin >> code; // 1120677212042015 


    UUU = int(code / 10000000000000);
    PP1 = int(code / 10000000000) % 100;
    PP2 = int(code / 100000000) % 100;
    DD = int(code / 1000000) % 100;


    cout << "\nRESULTS" << endl;
    cout << "\nUnique number: " << UUU << endl; // 112
    cout << "Country of origin: " << (char)PP1 << (char)PP2<<endl; //CH
    cout << "Day, Month and Year of expiration: " << DD; // 12/../....


    _getch();
    return 0;
}

Answer 1

One way is using substr concept.

For example, if user enters input as 1120677212042015, then read it into a string and divide the string into sub-strings according to the format UUUFPPPPDDMMAAAA .

std::string sUserCode = "1120677212042015";
std::string sUniqueNumber = str.substr (0,3);
int iUniqueNumber = stoi(sUniqueNumber);

Answer 2

This is one of those occasions where the C library comes in handy :

    int UUU, F, PP1, PP2, DD, MM, AAAA;
    cout << "Enter the code: "; // 1120677212042015
    scanf("%3d %1d %2d %2d %2d %2d %4d", &UUU, &F, &PP1, &PP2, &DD, &MM, &AAAA);

This captures all the values. The spaces in the format string are not necessary, but makes it easier to read.

Answer 3

u can use % and / to do this 4568962358 / 10000 = 456896 %100 = 96 or you can put it in a array and show the part of integer that u want.

int n = 4568962358;
int a[10];
for (int i = 0; i<10 ; i++)
{
    a[i] = n%10;
    n /= 10;
}

search your question in stack over flow. these questions have good answers.