This is the superclass:Glyph
public class Glyph {
    void draw() {
        System.out.println("Glyph.draw(");
    }
    Glyph() {
        System.out.println("Glyph() before draw()");
        draw();
        System.out.println("Glyph() after draw()");
    }
}
This is the subclass RoundGlyph
class RoundGlyph extends Glyph {
    int radius = 1;
    RoundGlyph(int r) {
        super();
        radius = r;
        System.out.println("RoundGlyph.RoundGlyph(), radius = " + radius);
    }
    void draw() {
        System.out.println("RoundGlyph.draw(), radius = " + radius);
    }
}
We use this class to test.
public class PolyConstructors {
    public static void main(String[] args) {
        new RoundGlyph(5);
    }
}
Output:
Glyph() before draw()
 RoundGlyph.draw(), radius = 0
 Glyph() after draw()
 RoundGlyph.RoundGlyph(), radius = 5
Why the program execute the method draw() in class RoundGlyph when it is executing the super()?
and print
RoundGlyph.draw(), radius = 0
 
     
    