Python: if elif loop

Asked Apr 28 '18 at 20:29

Active Apr 28 '18 at 20:44

Viewed 61 times

I am trying to do a sentiment analysis with twitter data. I know that the tokens in my POStagged_tweets_lines.json file are 90% neutral. My loop:

with open('POStagged_tweets_lines.json', 'r') as f:
for line in f:
    blob = TextBlob(line, classifier=classifier)

#blob = TextBlob('POStagged_tweets.json', classification = blob.classify() #print(classification)

pos = "pos"
neg = "neg"
neu = "neu"
negative = 0
positive = 0
neutral = 0

if classification == neu:
    neutral += 1
elif classification == pos:
    positive += 1
elif classification == neg:
    negative += 1

print(negative, positive, neutral)

Should be counting the sentiments of the tweets in the json file. So, at the end I should be getting an output such as 5, 12, 100; but Instead I am getting 0 0 1 and I don't even know where is it coming from.

edited Apr 28 '18 at 20:44

asked Apr 28 '18 at 20:29

bybu

3

1) We need a [mcve]. Your code throws syntax and other errors. We can't debug that. 2) Don't compare strings with `is`. – Aran-Fey Apr 28 '18 at 20:30
I've attached a screenshot; What should be used instead for strings? – bybu Apr 28 '18 at 20:33
64-69 lines must be at the outside of loop. – set0gut1 Apr 28 '18 at 20:34
**there is no loop** - if staements are conditios. loops typically use `while` or `for` – Patrick Artner Apr 28 '18 at 20:36
@set0gut1 I've tried this, it didn't work. I still get `0 0 1` as output – bybu Apr 28 '18 at 20:54

Python: if elif loop

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