I want to share memory using a file descriptor with another process created via fork.
The problem is that I get different address regions from mmap.
I want that mmap returns the same address value. Only in such case I can be sure that I really share the memory.
Probably it is possible to use MAP_FIXED flag to mmap, but how to get memory address from shm_open?
Is it possible to share memory via shm_open at all?
Maybe shmget must be used instead?
This is the minimal working example:
#include <stdio.h>
#include <sys/mman.h>
#include <unistd.h>
#include <fcntl.h>
int main(void)
{
  /* Create a new memory object */
  int fd = shm_open( "/dummy", O_RDWR | O_CREAT, 0777 );
  if(fd == -1) {
    fprintf(stderr, "Open failed:%m\n");
    return 1;
  }
  /* Set the memory object's size */
  size_t size = 4096; /* minimal */
  if (ftruncate(fd, size) == -1) {
    fprintf(stderr, "ftruncate: %m\n");
    return 1;
  }
  void *ptr = mmap(NULL, size, PROT_READ | PROT_WRITE, MAP_SHARED, fd, 0);
  if (ptr == MAP_FAILED) return 1;
  void *ptr2 = mmap(NULL, size, PROT_READ | PROT_WRITE, MAP_SHARED, fd, 0);
  if (ptr2 == MAP_FAILED) return 1;
  printf("%p\n%p\n", ptr, ptr2);
  return 0;
}
Compile it with gcc test.c -lrt.
This is the output:
0x7f3247a78000
0x7f3247a70000
EDIT
If I try to use method described in comment, child does not see changes in memory made by parent. Why? This is how I do it:
In parent:
shm_data = mmap(NULL, shm_size, PROT_WRITE, MAP_ANONYMOUS | MAP_SHARED, -1, 0);
...
snprintf(shared_memory, 20, "%p", shm_data);
execl("/path/to/prog", "prog", shared_memory, (char *) NULL);
In child:
...
void *base_addr;
sscanf(argv[1], "%p", (void **)&base_addr);
shm_data = mmap(base_addr, shm_size, PROT_READ, MAP_ANONYMOUS | MAP_SHARED | MAP_FIXED, -1, 0);
...
EDIT2
See also this question: How to get memory address from memfd_create?
