format datetime(0000-00-00 00:00:00 ) to 00:00:00 with time remaing

Question

I have a $time variable set some time in the future. In this format 2011-02-15 23:19:44. Now I need to set time remaining in this format 00:00:10.

If for example the $time is 1 hour, 3 minutes and 10 sec in the future. The format would be 01:03:10

and if its +24 hrs difference? – jpwco Feb 15 '11 at 22:31 — jpwco, Feb 15 '11 at 22:31

Jacob · Accepted Answer · 2011-02-15T22:35:36.440

1

You should look at using the DateTime and DateInterval classes.

$futureDate = new DateTime($time);
$currentDate = new DateTime();

$dateDiff = $currentDate->diff($futureDate);

echo $dateDiff->format('%H:%I:%S');

Note: if the difference is more than 24 hours, then you should look at the %Y-%m-%d values or %a for total days.

If you wanted to show any additional days as multiples of 24 hours then:

printf('%d:%s', 
    $dateDiff->format('%a') * 24 + $dateDiff->format('%H'), 
    $dateDiff->format('%I:%S')
);

edited Feb 15 '11 at 22:35

answered Feb 15 '11 at 22:29

Jacob

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('%H:%I:%S') ? to get the leading '0' on minutes and seconds? – jpwco Feb 15 '11 at 22:33
@jpwco thanks, I'm too used to the regular datetime formats :D – Jacob Feb 15 '11 at 22:36

score 0 · Answer 2 · edited May 23 '17 at 11:47

0

This is essentially the same problem as discussed here: PHP Time Since Function?

You're wanting to compare a future timestamp against the current time... the solutions in the linked question will also apply to this one.

edited May 23 '17 at 11:47

Community

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answered Feb 15 '11 at 22:26

Chris Baker

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format datetime(0000-00-00 00:00:00 ) to 00:00:00 with time remaing

2 Answers2