I'm hoping to do some cleanup job when an element is removed from the DOM tree, more specifically, ParentElement.removeChild(ChildElement). I'm wondering whether there's any event being emitted that I can listen in my code when the ChildElement is removed?
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        Brian Tompsett - 汤莱恩
        
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2 Answers
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        Yes, you can listen for manipulations to the DOM using a MutationObserver.
Example from the MDN docs:
// Select the node that will be observed for mutations
var targetNode = document.getElementById('some-id');
// Options for the observer (which mutations to observe)
var config = { attributes: true, childList: true };
// Callback function to execute when mutations are observed
var callback = function(mutationsList) {
    for(var mutation of mutationsList) {
        if (mutation.type == 'childList') {
            console.log('A child node has been added or removed.');
        }
        else if (mutation.type == 'attributes') {
            console.log('The ' + mutation.attributeName + ' attribute was modified.');
        }
    }
};
// Create an observer instance linked to the callback function
var observer = new MutationObserver(callback);
// Start observing the target node for configured mutations
observer.observe(targetNode, config);
// Later, you can stop observing
observer.disconnect();
 
    
    
        Elliot B.
        
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            Previously you could use mutation events like DOMNodeRemoved which were deprecated in favour of MutationObserver:
var observer = new MutationObserver((mutations) => {
  mutations.forEach((mutation) => {
    const removedNodes = mutation.removedNodes;
    // Cast NodeList to Array to have access to .includes method
    if (Array.from(removedNodes).includes(childElement)) {
      console.log('childElement removed');
    }
  })
});
observer.observe(document.getElementById('parentElement'), {
  childList: true
});
 
    
    
        Karen Grigoryan
        
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