cant access information behind reference c++

Question

Trying to do a subtraction of two vectors. In the end it should work like:

vector1.sub(vector2);

Custom Variable Vektor was defined as: Vektor(double x, double y, double z). Now I want to access the x, y, z coordinates through input.x, etc. Tells me

conversion from 'Vektor*' to non scalar type 'Vektor' requested.

Why tough??? Is it not possible to subtract a reference on to a value from a value?

Btw im new to SO so feel free to roast me for whatever ive done wrong!;)

Vektor Vektor::sub(const Vektor& input) const
{
    Vektor subresult = new Vektor(x - input.x, y - input.y, z - input.z);
    return subresult;
}

The `new` returns a pointer, and is just not needed. C++ is not Java. :-) — Bo Persson, May 11 '18 at 11:38

score 5 · Accepted Answer · answered May 11 '18 at 11:38

You should not use new here, just return by value

Vektor Vektor::sub(const Vektor& input) const
{
    return Vektor(x - input.x, y - input.y, z - input.z);
}

Also note that you can override operator- so you can perform a subtraction using the syntax v1 - v2 where each are of type Vektor.

cant access information behind reference c++

1 Answers1