php associated array error

Question

I write a program in PHP and now I learn assosiated arrays theme. This my cration and what is the program in it:

    <?PHP
 out("test starts");
 $people[] = array (
            "name" => "Brook",
            "age" => "42"
                 );
 $people[] = array (
            "name" => "Peter",
            "age" => "18"
                 );

 foreach($people as $person)
  out($person=>["name"] . " - " . $person=>["age"]);

/*
 I wanna this:
 Brook - 42
 Peter - 18

*/

 var_dump($people);
 out("test ends");


 function out($what) {
  echo $what . "<br>\n";
 }
?>

The var_dump is show me the array creation is good but the trouble is at foreach.

`out($person["name"] . " - " . $person["age"]);`... you don't use the `=>` here — Mark Baker, May 13 '18 at 20:34
Use this `out($person["name"] . " - " . $person["age"]);` instead. — Francis Ngueukam, May 13 '18 at 20:34
as you are still learning, it would be helpful for you to turn the PHP errors on. — hassan, May 13 '18 at 20:54
This is a result, I erased the => operator from my code and it do what I want. — Mr. Brooks, May 13 '18 at 21:03

score 3 · Answer 1 · answered May 13 '18 at 20:37

3

Your problem is most probably in this: out($person=>["name"] . " - " . $person=>["age"]);

instead use out($person["name"] . " - " . $person["age"]);

answered May 13 '18 at 20:37

Khaldoun Nd

1,436
12
23

score 0 · Answer 2 · answered May 13 '18 at 20:37

0

Assigning:

$name = array("key1" => value1,
"key2" => value2);

Accessing:

echo $name["key1"];
echo $name["key2"];

answered May 13 '18 at 20:37

Matthias Bö

449
3
12

score 0 · Answer 3 · answered May 13 '18 at 21:00

0

You have to remove =>. To access array properties you need to use square brackets $person["name"] (for objects use ->).

I found a very detailed answer about this topic here: How can I access an array/object?

answered May 13 '18 at 21:00

Ebby

514
3
9

php associated array error

3 Answers3