python check if a String is palindrome or not in an array

Question

For example I have this array:

array = ['b2', 'jy', 'n3', 'ih', 'fc']

And I am trying to access each index of the array to check if is palindrome or not.

for i in range(len(array[i])):

    if array[i] == array[len(pal)-i-1]:
        booleano = "true"

    else:
        booleano = "false"


if booleano != "true":
    return false

else: return true

What am I missing?

What exactly is wrong with the code you show? Read and follow [How to create a Minimal, Complete, and Verifiable example](http://stackoverflow.com/help/mcve). — Rory Daulton, May 17 '18 at 13:57
[How to debug small programs](https://ericlippert.com/2014/03/05/how-to-debug-small-programs) — akshat, May 17 '18 at 13:59
This can also be useful to verify conditions in a list: http://www.secnetix.de/olli/Python/list_comprehensions.hawk — Jundiaius, May 17 '18 at 14:00

Mihai Alexandru-Ionut · Answer 1 · 2018-05-17T14:06:41.970

3

You can check if string is palindrome using [::-1] slicing.

lst = ['bb', 'jhj', 'n3', 'ih', 'fc']
palindromes = [item == item[::-1] for item in lst]

Output

[True, True, False, False, False]

edited May 17 '18 at 14:06

answered May 17 '18 at 13:58

Mihai Alexandru-Ionut

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`[item == item[::-1]] for item in lst]` might be closer to what they asked for, also maybe debug their *current* code too – Chris_Rands May 17 '18 at 13:59
Instead of that kind of output how can I have like: `lst = ['bb true', 'jhj true', 'n3 false', 'ih false', 'fc false']` – Afonso Pinto May 17 '18 at 14:13
@AfonsoPinto, something like this: `palindromes = [item + ' '+ str(item == item[::-1]) for item in lst]` – Mihai Alexandru-Ionut May 17 '18 at 14:15

python check if a String is palindrome or not in an array

1 Answers1