PHP variable won't assign to array value

Question

I'm trying to assign $totalPrice a value from the array below but it is only returning 0, the echo $totalPrice is in some HTML code, if I use echo $sites[$site][0] it displays the value, but not when assigning it to $totalPrice?

$totalPrice = 0;
$site = "UM";

$totalPrice = $sites[$site][0];


    $sites = array
    (
        "US" => array (38.78, 11, 5.5),
        "UM" => array (44.55, 11, 5.5),
        "PS" => array (55.28, 11, 5.5),
        "PM" => array (66.55, 11, 5.5)
    )

    echo $totalPrice;

I can't seem to find `$totalPeople` in your code, also in the 3rd line, you are using `$sites` before declaring it. — Spoody, May 24 '18 at 11:13
the (corrected) code works as expected: https://3v4l.org/SgdUu - the error must be somewhere else. — Jeff, May 24 '18 at 11:14
@Jeff how is it possible to work when `$sites` is used before being initialized? — axiac, May 24 '18 at 11:15
@Mehdi true. I expected it a copy&paste mistake here, since shown code also produces a syntax error. — Jeff, May 24 '18 at 11:15
@Jeff yeah I deleted the comment after you added the _corrected_ part — Spoody, May 24 '18 at 11:16
@RJD the statements are executed in the order you write them in the file. When the line `$totalPrice = $sites[$site][0];` is executed, `$sites` does not exist yet. Accordingly, PHP issues a notice (you probably don't see) and sets `$totalPrice` to `NULL` (i.e. unset/undefined). — axiac, May 24 '18 at 11:16
You're missing a `;` after your `$sites` array. Also, turn on error reporting and you will get a `PHP Notice: Undefined variable: sites in ... on line 6` — brombeer, May 24 '18 at 11:17
May you address the questions/criticism surrounding the fact that you're trying to use `$sites` before you define it…? — deceze, May 24 '18 at 11:23

Pushpendra Kumar · Answer 1 · 2018-05-24T11:18:26.513

2

$totalPrice = 0;
$site = "UM";

$sites = array
(
    "US" => array (38.78, 11, 5.5),
    "UM" => array (44.55, 11, 5.5),
    "PS" => array (55.28, 11, 5.5),
    "PM" => array (66.55, 11, 5.5)
);
$totalPrice = $sites[$site][0];


echo $totalPrice;

you used $totalPrice = $sites[$site][0]; variable $sites before initialize, that's why it gives you answer 0 every time.

edited May 24 '18 at 11:18

answered May 24 '18 at 11:15

Pushpendra Kumar

1,721
1
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1

you have a syntax error. – Jeff May 24 '18 at 11:15
1

And also this is not a good way to answer, add an explanation. Tell OP why his code is wrong and why yours is correct. – Spoody May 24 '18 at 11:16

score 2 · Accepted Answer · answered May 24 '18 at 11:16

You can try this code..you need to declare $totalPrice below array value...

$totalPrice = 0;
$site = "UM";


    $sites = array(
        "US" => array (38.78, 11, 5.5),
        "UM" => array (44.55, 11, 5.5),
        "PS" => array (55.28, 11, 5.5),
        "PM" => array (66.55, 11, 5.5)
    );

    $totalPrice = $sites[$site][0];
echo $totalPrice;

PHP variable won't assign to array value

2 Answers2