Why is my program skipping the gets() function?

Question

I was studying for a quiz and while writing the code I faced a problem.

My code skips the gets() function. If I use scanf it wont skip but since I'm scanning a full name using scanf would be troublesome but gets() is skipped for some reason.

struct Conta{

    char nomeDoCliente[50];
    int numeroDeConta;
    float saldoDeConta;

};
struct Conta conta1;

int main()
{
            switch (menu()){
            case 1 :
                defDadosDeConta();
                break;
            case 2 :
                break;
            case 3 :
                break;

            }
}

int menu(){
    int escolha;
    puts("1 - Definir dados da conta.");
    puts("2 - Depositar Dinheiro.");
    puts("3 - Levantar Dinheiro.");
    puts("4 - Sair.");
    printf("Escolha a sua operação: ");
    scanf("%d", &escolha);
    return escolha;
}
defDadosDeConta(){
    printf("Insira o seu nome: ");
    gets(conta1.nomeDoCliente);
    puts("Dados de conta guardados com sucesso!");


}

[Why are you using `gets`?](https://stackoverflow.com/q/1694036/10077) — Fred Larson, May 25 '18 at 15:30
Probably because scanf leaves the newline character in the buffer, so gets reads an empty line. — rustyx, May 25 '18 at 15:31
What do you mean by "skip"? What makes you think that `gets()` gets skipped? — Yunnosch, May 25 '18 at 15:31
"%d' says to stop at the first non-digit and leave it in the input stream. So the newline at the end of that line is still waiting to be read. — stark, May 25 '18 at 15:33
Init the clients name with e.g. "uninitialised". Then see whether that survives. If the name ends up as "", i.e. empty, then `gets()` did **not** get skipped. — Yunnosch, May 25 '18 at 15:33
Im using gets cos i want to get a full name input from the user. — Javabeginner, May 25 '18 at 15:47
I used the fflush(stdin); at the end of every functoin i have in my code and it solved my problem. — Javabeginner, May 25 '18 at 15:50
It was indeed the scanf leaving a newline char in the buffer — Javabeginner, May 25 '18 at 15:50

dbush · Accepted Answer · 2018-05-25T15:50:58.970

3

First, never use gets as it is insecure. The safer alternative is fgets.

Even if you use that, mixing scanf and fgets causes problems because the former may leave a newline in the input buffer, causing the latter to stop once it reads that newline.

Change to scanf to read the string:

scanf("%49[^\n]", conta1.nomeDoCliente);

The format specifier %49[^\n] states to read up to 49 non-newline characters.

edited May 25 '18 at 15:50

answered May 25 '18 at 15:33

dbush

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%49[^\n] did fix my problem. I think the issue was that after i canned for the conta1.nomeDoCliente some background issue were happening. – Javabeginner May 25 '18 at 16:05

Why is my program skipping the gets() function?

1 Answers1