PHP If Statement is met display Either

Question

I am familiar with using if else statement but my problem is how to display either if the condition is met.

if ($a == 1) {

echo 'B' OR 'C';  // just for reference

}

I have finally figure this out using nested loop

  if ($a == 1) {
    choiceresult = mt_rand(1,2)

   if (choiceresult == 1) {
      echo 'B';
   }

   if ( choiceresult == 2) {
      echo 'C';
   }

  }

"I am familiar with using if else statement " and yet you are using it wrong, its `==` not `=`. what determines when to echo `C` and when to echo `B` ? — , May 28 '18 at 00:07
look at http://php.net/manual/en/language.operators.comparison.php — daremachine, May 28 '18 at 00:10
`=` is used for assignments, `==` or `===` are for comparisons. — jh1711, May 28 '18 at 00:10
if single line statement then you can use ternary condition like "echo ($a==1)?'B':'C'; " — Jaydp, May 28 '18 at 00:10
Possible duplicate of [The 3 different equals](https://stackoverflow.com/questions/2063480/the-3-different-equals) — , May 28 '18 at 00:11
"I have finally figure this out using nested loop": there is no loop in the code you show — Karsten Koop, May 28 '18 at 08:07

score 1 · Accepted Answer · edited May 28 '18 at 02:09

1

you have to fix your condition first :

if($a == 1)

Instead pf

if($a = 1)

edited May 28 '18 at 02:09

cs95

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answered May 28 '18 at 01:00

Mostafa Aguerram

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my problem is not the equal but what comes after it whether I use = == === for short how to display one result from – JeVic May 28 '18 at 07:39

PHP If Statement is met display Either

1 Answers1