Why does long shows wrong output in finding second maximum of three integers?

Question

I am a novice to CP and while I was doing this problem of finding the second maximum among three numbers I wrote this code which however works for int but doesn't work for long even though they are the same data types.

Input Format:

The first line contains the number of triples, N.
The next N lines which follow each have three space separated integers.

Input Used:

3

1 2 3

10 15 5

100 999 500

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
       int n;
       cin >>n ;
       while(n--){
          long a,b,c,d;//if i change long to int output is correct  
          scanf("%i%i%i",&a,&b,&c);
          d=min(max(a,b),max(a,c));
          printf("%i\n",d);// outputs 1 \n 10 \n 100 \n(\n means new line)
     }
    return 0;
    }

Unrelated to your problem, but please read [Why should I not #include ?](https://stackoverflow.com/questions/31816095/why-should-i-not-include-bits-stdc-h) — Some programmer dude, May 28 '18 at 17:18
More related to your problem, please [get a good C++ book or two or three](https://stackoverflow.com/questions/388242/the-definitive-c-book-guide-and-list/388282#388282) and learn C++ properly. — Some programmer dude, May 28 '18 at 17:19
And no, `long` (or rather `long int` as its full name is) might be an integer just like `int`, but they are not really the same types. — Some programmer dude, May 28 '18 at 17:21
You could have simply used `cout` and not have to specify types in a format string. You don't know what the values really are due to possibly using an incorrect format string in `printf`. — PaulMcKenzie, May 28 '18 at 17:42

score 1 · Accepted Answer · answered May 28 '18 at 17:20

1

Perhaps because you're using the wrong specifier. %i is for ints, but %li is for longs.

answered May 28 '18 at 17:20

frslm

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Why does long shows wrong output in finding second maximum of three integers?

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