Regex is cutting my string at a dot

Question

I have the following regular expression:

\s?(\w+)=(\w+)?\s?

My input is

Brutto=57.800

The match is just

Brutto=57

What can I do to get the following result?

Brutto=57.800

. . . . . . . . . . . . . . . . . . . . to `[\w.]+` or better `\d+([.]\d+)?` — wp78de, May 31 '18 at 02:17
Possible duplicate of [Decimal number regular expression, where digit after decimal is optional](https://stackoverflow.com/questions/12117024/decimal-number-regular-expression-where-digit-after-decimal-is-optional) — wp78de, May 31 '18 at 02:21

score 1 · Accepted Answer · answered May 31 '18 at 02:28

1

I would just get all "non-space" chars:

\s?(\w+)=(\S*)\s?

FYI (\S*) has the same effect as (\S+)?, but is simpler.

answered May 31 '18 at 02:28

Bohemian

score 0 · Answer 2 · answered May 31 '18 at 02:18

0

You can use something like if the value always contains a decimal point \s?(\w+)=(\d+.\d+)?\s?

answered May 31 '18 at 02:18

score 0 · Answer 3 · answered May 31 '18 at 02:19

0

You must handle the dot separately (and escape it with a backslash):

\s?(\w+)=(\w+\.?\w+)?\s?

answered May 31 '18 at 02:19

Boergler

score 0 · Answer 4 · answered May 31 '18 at 02:23

0

If u need just matching u can try \s?\w+=\d+.\d+\s?.

If u need grouping also u can try \s?(\w+)=(\d+.\d+)\s?

u can also replace \d with \w as \d represents only digits whereas \w represents any Alphanumeric characters.

answered May 31 '18 at 02:23

Eddy

score 0 · Answer 5 · answered May 31 '18 at 09:08

In your regex you use \w+ which does not match the dot in 57.800 that so it would match 57.

If your goal is to match digits after the equals sign with an optional whitespace character \s? at the start and at the end, you might use:

Note that I have not use captured groups (). If you want to retrieve your matches using groups, you could use (\w+) and ([0-9]+\.[0-9]+)

If the .800 is optional you could use \s?\w+=[0-9]+(?:\.[0-9]+)?\s?

5 Answers5