Please give the reason for the output...why it's giving 'bye' while the condition if statement is true because the size of int is 2 or 4 byte.
#include<stdio.h>
#include<conio.h>
int main()
{
if(sizeof(int)>-1)
printf("hi");
else
printf("bye");
return 0;
}
See http://en.cppreference.com/w/c/language/sizeof
Both versions return a value of type size_t.
See size_t, http://en.cppreference.com/w/c/types/size_t
which states that it is unsigned.
If therefor the comparison is effectively with a high positive value,
then the logical expression is basically always false.
If you would help the compiler understand what you really want to do,
e.g. by changing to
((int)sizeof(int))>-1
things are different.
It's because the return type of sizeof() is size_t and sizeof() never gives size in negative bytes.
sizeof(int) results is type of unsigned.
And here
if(sizeof(int)>-1)
Comparison is happening between different types i.e signed(-1) and unsigned. So internally compiler will do implicit typecasting i.e signed gets converted into unsigned and -1 equivalent unsigned value is all one's i.e 4294967295.
So now condition looks like
if(4 > 4294967295)
Which is false so it prints bye.
See this for sizeof() return type http://en.cppreference.com/w/c/types/size_t
