Filter array which satisfies condition

Question

I have two array variables A and B.

A = [1,2,3,4]
B = [1,3,4,5,7,8]

How do I use filter in array B which has same element in A like B = [1,3,4]?

Possible duplicate of [Simplest code for array intersection in javascript](https://stackoverflow.com/questions/1885557/simplest-code-for-array-intersection-in-javascript) — Redu, Jun 11 '18 at 11:26

score 3 · Answer 1 · answered Jun 11 '18 at 11:12

3

Use Array#filter with Array#includes:

const A = [1,2,3,4];
let B = [1,3,4,5,7,8];

B = B.filter(item => A.includes(item));
console.log(B);

answered Jun 11 '18 at 11:12

31piy

score 0 · Answer 2 · answered Jun 11 '18 at 11:20

0

You can also get your required result using filter() and indexOf

DEMO

let A = [1,2,3,4],
      B = [1,3,4,5,7,8];

let result = B.filter(v => A.indexOf(v) >= 0);

console.log(result);

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answered Jun 11 '18 at 11:20

Narendra Jadhav

score 0 · Answer 3 · answered Jun 11 '18 at 11:26

0

You can use Array.prototype.filter along with Array.prototype.indexOf

array1.filter(value => -1 !== array2.indexOf(value));

answered Jun 11 '18 at 11:26

nbirla

3 Answers3