Python regular expression difference zA-Z0-9]\S@\S[a-zA-Z] vs ('\S+@\S+'

Question

I'm new on this topic for python 3.6. What is the difference \S*..\S* and \S+..\S+?

**import re
s = 'A message from csev@umich.edu to cwen@iupui.edu about meeting @2PM'
lst = re.findall('\S+@\S+', s)
print(lst)**

[a-zA-Z0-9]\S*@\S*[a-zA-Z]

Possible duplicate of [Learning Regular Expressions](https://stackoverflow.com/questions/4736/learning-regular-expressions) — Tim Biegeleisen, Jun 15 '18 at 02:25

score 1 · Answer 1 · answered Jun 15 '18 at 02:21

1

\S means it will match non-whitespace characters.
+ means it will match 1 or more of the preceding token.
* means it will match 0 or more of the preceding token.

So in that case the \S+ means it will match 1 or more non-whitespace characters where as \S* will match 0 or more.

answered Jun 15 '18 at 02:21

Daniel A. White

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Why does '2PM@ 3PM' is not matched for regex [a-zA-Z0-9]\S*@\S*[a-zA-Z] ? – djay Oct 03 '19 at 05:12

Python regular expression difference zA-Z0-9]\S*@\S*[a-zA-Z] vs ('\S+@\S+'

1 Answers1

Python regular expression difference zA-Z0-9]\S@\S[a-zA-Z] vs ('\S+@\S+'